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农场里有一群牛，每头牛都有一个编号。农场主想要根据牛的编号对牛群进行升序排序。给定一个代表每头牛编号的整数数组，请你将该数组升序排列。不允许调用库函数。

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农场里有一群牛，每头牛都有一个编号。农场主想要根据牛的编号对牛群进行升序排序。给定一个代表每头牛编号的整数数组，请你将该数组升序排列。不允许调用库函数。

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qklbishe.com区块链毕设代做网专注|以太坊fabric-计算机|java|毕业设计|代做平台-javagopython毕设 » 农场里有一群牛，每头牛都有一个编号。农场主想要根据牛的编号对牛群进行升序排序。给定一个代表每头牛编号的整数数组，请你将该数组升序排列。不允许调用库函数。

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Expression evaluation is a classic problem. In this problem, you only need to evaluate an expression of length less than . It only contains non-negative integers (possibly with leading zeros), `+’s, `-‘s and `*’s, i.e., it satisfies the following grammar: <expression>:= <term>|<expression>+<term>|<expression>-<term> <term>:= <number>|<term>*<number> <number>:= <digit>|<number><digit> <digit>:= 0|1|2|3|4|5|6|7|8|9 For example,013, 0213-2132*0213 are valid, but -2132 and 32113+-3213 are invalid. The result of the evaluation may be too large or negative. Output the result modulo  to avoid overflow since you will use a -bit machine. The -bit machine contains units of memory, denoted as , , , . Each unit is a -bit unsigned number, also an instruction. In each cycle, let , the machine execute the instruction . Let at the beginning of cycle, where , , , are non-negative integers and less than : If , the machine outputs the value of and stops. If , and then:             – If there are no characters in input left, set to ;             – Otherwise, set to the ASCII code of the next character of input, and then set to .  If , set to , and then set to .  If , and then:             – If , set to the value of ;             –  Otherwise, set to the value of . Note that if in some instructions, may be set more than once. Its value is the value set last after the cycle. You need to set the initial value for each unit such that the machine can stop in finite cycles and output the result of expression modulo . Since there is a time limit for a problem. In this problem, the machine can execute at most cycles.
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Expression evaluation is a classic problem. In this problem, you only need to evaluate an expression of length less than . It only contains non-negative integers (possibly with leading zeros), `+’s, `-‘s and `*’s, i.e., it satisfies the following grammar: <expression>:= <term>|<expression>+<term>|<expression>-<term> <term>:= <number>|<term>*<number> <number>:= <digit>|<number><digit> <digit>:= 0|1|2|3|4|5|6|7|8|9 For example,013, 0213-2132*0213 are valid, but -2132 and 32113+-3213 are invalid. The result of the evaluation may be too large or negative. Output the result modulo  to avoid overflow since you will use a -bit machine. The -bit machine contains units of memory, denoted as , , , . Each unit is a -bit unsigned number, also an instruction. In each cycle, let , the machine execute the instruction . Let at the beginning of cycle, where , , , are non-negative integers and less than : If , the machine outputs the value of and stops. If , and then:             – If there are no characters in input left, set to ;             – Otherwise, set to the ASCII code of the next character of input, and then set to .  If , set to , and then set to .  If , and then:             – If , set to the value of ;             –  Otherwise, set to the value of . Note that if in some instructions, may be set more than once. Its value is the value set last after the cycle. You need to set the initial value for each unit such that the machine can stop in finite cycles and output the result of expression modulo . Since there is a time limit for a problem. In this problem, the machine can execute at most cycles.

区块链毕设网qklbishe.com为您提供问题的解答 Expression eva...
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牛牛是一头聪明的牛，他想设计一个跳表来进行快速的增加、删除和搜索操作。跳表是一种能够在 O(log(n)) 时间内完成这些操作的数据结构。牛牛希望你设计一个跳表，并实现以下几个函数：  class Skiplist {        public: Skiplist();        bool search(int target); // 返回target是否存在于跳表中。       void add(int num); // 插入一个元素到跳表。 插入成功输出true      bool erase(int num); // 在跳表中删除一个值，如果 num 不存在，直接返回false. 如果存在多个 num ，删除其中任意一个即可。  }; 
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牛牛是一头聪明的牛，他想设计一个跳表来进行快速的增加、删除和搜索操作。跳表是一种能够在 O(log(n)) 时间内完成这些操作的数据结构。牛牛希望你设计一个跳表，并实现以下几个函数：  class Skiplist {        public: Skiplist();        bool search(int target); // 返回target是否存在于跳表中。       void add(int num); // 插入一个元素到跳表。 插入成功输出true      bool erase(int num); // 在跳表中删除一个值，如果 num 不存在，直接返回false. 如果存在多个 num ，删除其中任意一个即可。  }; 

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