50.纠错4 表Customers含有字段cust_name顾客名、cust_contact顾客联系方式、cust_state顾客州、cust_email顾客email cust_name cust_contact cust_state cust_email cust10 8695192 MI [email protected] cust1 8695193 MI cust1 @cust.com cust2 8695194 IL cust2 @cust.com 【问题】修正下面错误的SQL SELECT cust_name, cust_contact, cust_email FROM Customers WHERE cust_state = ‘MI’ ORDER BY cust_name; UNION SELECT cust_name, cust_contact, cust_email FROM Customers WHERE cust_state = ‘IL’ORDER BY cust_name; 【示例结果】 返回顾客名称:cust_name、顾客联系方式:cust_contact、顾客email:cust_email cust_name cust_contact cust_email cust1 8695193 [email protected] cust10 8695192 cust10 @cust.com cust2 8695194 cust2 @cust.com 【示例解析】 返回住在"IL"和"MI"的顾客信息,最后根据顾客名称升序排序。
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表Customers含有字段cust_name顾客名、cust_contact顾客联系方式、cust_state顾客州、cust_email顾客email
cust_name | cust_contact | cust_state | cust_email |
cust10 | 8695192 | MI | cust10@cust.com |
cust1 | 8695193 | MI | cust1@cust.com |
cust2 | 8695194 | IL | cust2@cust.com |
【问题】修正下面错误的SQL
SELECT cust_name, cust_contact, cust_email FROM Customers WHERE cust_state = 'MI' ORDER BY cust_name; UNION SELECT cust_name, cust_contact, cust_email FROM Customers WHERE cust_state = 'IL'ORDER BY cust_name;
【示例结果】
返回顾客名称:cust_name、顾客联系方式:cust_contact、顾客email:cust_email
cust_name | cust_contact | cust_email |
cust1 | 8695193 | cust1@cust.com |
cust10 | 8695192 | cust10@cust.com |
cust2 | 8695194 | cust2@cust.com |
【示例解析】
返回住在"IL"和"MI"的顾客信息,最后根据顾客名称升序排序。
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具体资料介绍
web3的一级市场千万收益的逻辑
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表Customers含有字段cust_name顾客名、cust_contact顾客联系方式、cust_state顾客州、cust_email顾客email cust_name cust_contact
cust_state cust_email
cust10 8695192 MI [email protected]
cust1 8695193
MI cust1 @cust.com
cust2
8695194
IL cust2 @cust.com
【问题】修正下面错误的SQL SELECT cust_name, cust_contact, cust_email FROM Customers WHERE cust_state = ‘MI’ ORDER BY cust_name; UNION SELECT cust_name, cust_contact, cust_email FROM Customers WHERE cust_state = ‘IL’ORDER BY cust_name; 【示例结果】 返回顾客名称:cust_name、顾客联系方式:cust_contact、顾客email:cust_email cust_name cust_contact
cust_email
cust1 8695193 [email protected]
cust10 8695192
cust10 @cust.com
cust2
8695194
cust2 @cust.com
【示例解析】 返回住在"IL"和"MI"的顾客信息,最后根据顾客名称升序排序。
微信:btc9767
TELEGRAM :https://t.me/btcok9
具体资料介绍
web3的一级市场千万收益的逻辑
进群点我
qklbishe.com区块链毕设代做网专注|以太坊fabric-计算机|java|毕业设计|代做平台-javagopython毕设 » 50.纠错4
表Customers含有字段cust_name顾客名、cust_contact顾客联系方式、cust_state顾客州、cust_email顾客email cust_name cust_contact
cust_state cust_email
cust10 8695192 MI [email protected]
cust1 8695193
MI cust1 @cust.com
cust2
8695194
IL cust2 @cust.com
【问题】修正下面错误的SQL SELECT cust_name, cust_contact, cust_email FROM Customers WHERE cust_state = ‘MI’ ORDER BY cust_name; UNION SELECT cust_name, cust_contact, cust_email FROM Customers WHERE cust_state = ‘IL’ORDER BY cust_name; 【示例结果】 返回顾客名称:cust_name、顾客联系方式:cust_contact、顾客email:cust_email cust_name cust_contact
cust_email
cust1 8695193 [email protected]
cust10 8695192
cust10 @cust.com
cust2
8695194
cust2 @cust.com
【示例解析】 返回住在"IL"和"MI"的顾客信息,最后根据顾客名称升序排序。
进群点我
qklbishe.com区块链毕设代做网专注|以太坊fabric-计算机|java|毕业设计|代做平台-javagopython毕设 » 50.纠错4
表Customers含有字段cust_name顾客名、cust_contact顾客联系方式、cust_state顾客州、cust_email顾客email cust_name cust_contact
cust_state cust_email
cust10 8695192 MI [email protected]
cust1 8695193
MI cust1 @cust.com
cust2
8695194
IL cust2 @cust.com
【问题】修正下面错误的SQL SELECT cust_name, cust_contact, cust_email FROM Customers WHERE cust_state = ‘MI’ ORDER BY cust_name; UNION SELECT cust_name, cust_contact, cust_email FROM Customers WHERE cust_state = ‘IL’ORDER BY cust_name; 【示例结果】 返回顾客名称:cust_name、顾客联系方式:cust_contact、顾客email:cust_email cust_name cust_contact
cust_email
cust1 8695193 [email protected]
cust10 8695192
cust10 @cust.com
cust2
8695194
cust2 @cust.com
【示例解析】 返回住在"IL"和"MI"的顾客信息,最后根据顾客名称升序排序。
qklbishe.com区块链毕设代做网专注|以太坊fabric-计算机|java|毕业设计|代做平台-javagopython毕设 » 50.纠错4 表Customers含有字段cust_name顾客名、cust_contact顾客联系方式、cust_state顾客州、cust_email顾客email cust_name cust_contact cust_state cust_email cust10 8695192 MI [email protected] cust1 8695193 MI cust1 @cust.com cust2 8695194 IL cust2 @cust.com 【问题】修正下面错误的SQL SELECT cust_name, cust_contact, cust_email FROM Customers WHERE cust_state = ‘MI’ ORDER BY cust_name; UNION SELECT cust_name, cust_contact, cust_email FROM Customers WHERE cust_state = ‘IL’ORDER BY cust_name; 【示例结果】 返回顾客名称:cust_name、顾客联系方式:cust_contact、顾客email:cust_email cust_name cust_contact cust_email cust1 8695193 [email protected] cust10 8695192 cust10 @cust.com cust2 8695194 cust2 @cust.com 【示例解析】 返回住在"IL"和"MI"的顾客信息,最后根据顾客名称升序排序。