下面代码执行后的结果是（） #include “stdio.h” int Function(unsigned int n) { n = (n & 0x55555555) + ((n >> 1) & 0x55555555); n = (n & 0x33333333) + ((n >> 2) & 0x33333333); n = (n & 0x0f0f0f0f) + ((n >> 4) & 0x0f0f0f0f); n = (n & 0x00ff00ff) + ((n >> 8) & 0x00ff00ff); n = (n & 0x0000ffff) + ((n >> 16) & 0x0000ffff); return n; } void main() { printf(“%ldn”,Function(197)); }

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下面代码执行后的结果是（）

#include “stdio.h”

int Function(unsigned int n) {

n = (n & 0x55555555) + ((n >> 1) & 0x55555555);

n = (n & 0x33333333) + ((n >> 2) & 0x33333333);

n = (n & 0x0f0f0f0f) + ((n >> 4) & 0x0f0f0f0f);

n = (n & 0x00ff00ff) + ((n >> 8) & 0x00ff00ff);

n = (n & 0x0000ffff) + ((n >> 16) & 0x0000ffff);

return n;

}

void main() {

printf(“%ldn”,Function(197));

}

#include "stdio.h" int Function(unsigned int n) { n = (n & 0x55555555) + ((n >> 1) & 0x55555555); n = (n & 0x33333333) + ((n >> 2) & 0x33333333); n = (n & 0x0f0f0f0f) + ((n >> 4) & 0x0f0f0f0f); n = (n & 0x00ff00ff) + ((n >> 8) & 0x00ff00ff); n = (n & 0x0000ffff) + ((n >> 16) & 0x0000ffff); return n; } int main() { printf("%un", Function(197)); return 0; }

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以上就是关于问题下面代码执行后的结果是（） #include “stdio.h” int Function(unsigned int n) { n = (n & 0x55555555) + ((n >> 1) & 0x55555555); n = (n & 0x33333333) + ((n >> 2) & 0x33333333); n = (n & 0x0f0f0f0f) + ((n >> 4) & 0x0f0f0f0f); n = (n & 0x00ff00ff) + ((n >> 8) & 0x00ff00ff); n = (n & 0x0000ffff) + ((n >> 16) & 0x0000ffff); return n; } void main() { printf(“%ldn”,Function(197)); }的答案

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