31.纠错3 OrderItems表含有order_num订单号 order_num a002 a002 a002 a004 a007 【问题】将下面代码修改正确后执行 SELECT order_num, COUNT(*) AS items FROM OrderItems GROUP BY items HAVING COUNT(*) >= 3 ORDER BY items, order_num; 【示例结果】 返回订单号order_num和出现的次数items order_num items a002 3 【示例解析】 由于订单号a002出现了三次，所以返回3
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31.纠错3
OrderItems表含有order_num订单号
| order_num |
| a002 |
| a002 |
| a002 |
| a004 |
| a007 |
【问题】将下面代码修改正确后执行
SELECT order_num, COUNT(*) AS items FROM OrderItems GROUP BY items HAVING COUNT(*) >= 3 ORDER BY items, order_num;
【示例结果】
返回订单号order_num和出现的次数items
| order_num | items |
| a002 | 3 |
【示例解析】
由于订单号a002出现了三次，所以返回3
A应该是对的啊 我在mysql中运行了相同的代码 结果是可以出来的啊
29:53
以上就是关于问题31.纠错3
OrderItems表含有order_num订单号 order_num a002 a002
a002
a004
a007
【问题】将下面代码修改正确后执行 SELECT order_num, COUNT(*) AS items FROM OrderItems GROUP BY items HAVING COUNT(*) >= 3 ORDER BY items, order_num; 【示例结果】 返回订单号order_num和出现的次数items order_num items a002 3 【示例解析】 由于订单号a002出现了三次，所以返回3的答案
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OrderItems表含有order_num订单号 order_num a002 a002
a002
a004
a007
【问题】将下面代码修改正确后执行 SELECT order_num, COUNT(*) AS items FROM OrderItems GROUP BY items HAVING COUNT(*) >= 3 ORDER BY items, order_num; 【示例结果】 返回订单号order_num和出现的次数items order_num items a002 3 【示例解析】 由于订单号a002出现了三次，所以返回3
微信：btc9767
TELEGRAM ：https://t.me/btcok9
具体资料介绍
web3的一级市场千万收益的逻辑
进群点我
qklbishe.com区块链毕设代做网专注|以太坊fabric-计算机|java|毕业设计|代做平台-javagopython毕设 » 31.纠错3
OrderItems表含有order_num订单号 order_num a002 a002
a002
a004
a007
【问题】将下面代码修改正确后执行 SELECT order_num, COUNT(*) AS items FROM OrderItems GROUP BY items HAVING COUNT(*) >= 3 ORDER BY items, order_num; 【示例结果】 返回订单号order_num和出现的次数items order_num items a002 3 【示例解析】 由于订单号a002出现了三次，所以返回3
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qklbishe.com区块链毕设代做网专注|以太坊fabric-计算机|java|毕业设计|代做平台-javagopython毕设 » 31.纠错3
OrderItems表含有order_num订单号 order_num a002 a002
a002
a004
a007
【问题】将下面代码修改正确后执行 SELECT order_num, COUNT(*) AS items FROM OrderItems GROUP BY items HAVING COUNT(*) >= 3 ORDER BY items, order_num; 【示例结果】 返回订单号order_num和出现的次数items order_num items a002 3 【示例解析】 由于订单号a002出现了三次，所以返回3
qklbishe.com区块链毕设代做网专注|以太坊fabric-计算机|java|毕业设计|代做平台-javagopython毕设 » 31.纠错3 OrderItems表含有order_num订单号 order_num a002 a002 a002 a004 a007 【问题】将下面代码修改正确后执行 SELECT order_num, COUNT(*) AS items FROM OrderItems GROUP BY items HAVING COUNT(*) >= 3 ORDER BY items, order_num; 【示例结果】 返回订单号order_num和出现的次数items order_num items a002 3 【示例解析】 由于订单号a002出现了三次，所以返回3
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