SQL> SELECT * FROM A; ID NAME 1 A1 2 A2 3 A3 SQL> SELECT * FROM C; ID AID NAME CODE NUM 1 1 B1 B 1 2 1 B2 B 3 3 2 C1 C 5 4 2 C2 C 7 5 3 D1 D 9 6 3 D2 D 2 7 3 D3 D 4 8 4 E1 E 6 9 4 E2 E 8 基于以上数据,下面SQL的模型如何调整() SQL> SELECT ID,NAME,(SELECT SUM(NUM) FROM C WHERE A.ID=C.AID) AS S FROM A ; ID NAME S 1 A1 4 2 A2 12 3 A3 15
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SQL> SELECT * FROM A;
ID | NAME |
1 | A1 |
2 | A2 |
3 | A3 |
SQL> SELECT * FROM C;
ID | AID | NAME | CODE | NUM |
1 | 1 | B1 | B | 1 |
2 | 1 | B2 | B | 3 |
3 | 2 | C1 | C | 5 |
4 | 2 | C2 | C | 7 |
5 | 3 | D1 | D | 9 |
6 | 3 | D2 | D | 2 |
7 | 3 | D3 | D | 4 |
8 | 4 | E1 | E | 6 |
9 | 4 | E2 | E | 8 |
基于以上数据,下面SQL的模型如何调整()
SQL> SELECT ID,NAME,(SELECT SUM(NUM) FROM C WHERE A.ID=C.AID) AS S FROM A ;
ID | NAME | S |
1 | A1 | 4 |
2 | A2 | 12 |
3 | A3 | 15 |
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qklbishe.com区块链毕设代做网专注|以太坊fabric-计算机|java|毕业设计|代做平台-javagopython毕设 » SQL> SELECT * FROM A; ID
NAME
1 A1
2 A2
3 A3 SQL> SELECT * FROM C;
ID
AID
NAME
CODE
NUM
1 1 B1 B 1 2 1 B2 B 3 3 2 C1 C 5 4 2 C2 C 7 5 3 D1 D 9 6 3 D2 D 2 7 3 D3 D 4 8 4 E1 E 6 9 4 E2 E 8 基于以上数据,下面SQL的模型如何调整() SQL> SELECT ID,NAME,(SELECT SUM(NUM) FROM C WHERE A.ID=C.AID) AS S FROM A ;
ID
NAME
S
1 A1 4 2 A2 12 3 A3 15
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TELEGRAM :https://t.me/btcok9
具体资料介绍
web3的一级市场千万收益的逻辑
进群点我
qklbishe.com区块链毕设代做网专注|以太坊fabric-计算机|java|毕业设计|代做平台-javagopython毕设 » SQL> SELECT * FROM A; ID
NAME
1 A1
2 A2
3 A3 SQL> SELECT * FROM C;
ID
AID
NAME
CODE
NUM
1 1 B1 B 1 2 1 B2 B 3 3 2 C1 C 5 4 2 C2 C 7 5 3 D1 D 9 6 3 D2 D 2 7 3 D3 D 4 8 4 E1 E 6 9 4 E2 E 8 基于以上数据,下面SQL的模型如何调整() SQL> SELECT ID,NAME,(SELECT SUM(NUM) FROM C WHERE A.ID=C.AID) AS S FROM A ;
ID
NAME
S
1 A1 4 2 A2 12 3 A3 15
进群点我
qklbishe.com区块链毕设代做网专注|以太坊fabric-计算机|java|毕业设计|代做平台-javagopython毕设 » SQL> SELECT * FROM A; ID
NAME
1 A1
2 A2
3 A3 SQL> SELECT * FROM C;
ID
AID
NAME
CODE
NUM
1 1 B1 B 1 2 1 B2 B 3 3 2 C1 C 5 4 2 C2 C 7 5 3 D1 D 9 6 3 D2 D 2 7 3 D3 D 4 8 4 E1 E 6 9 4 E2 E 8 基于以上数据,下面SQL的模型如何调整() SQL> SELECT ID,NAME,(SELECT SUM(NUM) FROM C WHERE A.ID=C.AID) AS S FROM A ;
ID
NAME
S
1 A1 4 2 A2 12 3 A3 15
qklbishe.com区块链毕设代做网专注|以太坊fabric-计算机|java|毕业设计|代做平台-javagopython毕设 » SQL> SELECT * FROM A; ID NAME 1 A1 2 A2 3 A3 SQL> SELECT * FROM C; ID AID NAME CODE NUM 1 1 B1 B 1 2 1 B2 B 3 3 2 C1 C 5 4 2 C2 C 7 5 3 D1 D 9 6 3 D2 D 2 7 3 D3 D 4 8 4 E1 E 6 9 4 E2 E 8 基于以上数据,下面SQL的模型如何调整() SQL> SELECT ID,NAME,(SELECT SUM(NUM) FROM C WHERE A.ID=C.AID) AS S FROM A ; ID NAME S 1 A1 4 2 A2 12 3 A3 15